Question #342022

A moving airplane dropped a cargo (ignore the effect of air resistance). If the plane from which the cargo was dropped was flying at a height of 600 m, and the cargo lands 300 m horizontally from the initial dropping point,





a. how fast was the plane flying when the cargo was released? (Vix=?)




b. what was the velocity of the cargo right before it hit the ground? (Vfy=?)



Solve for time first using this equation: t= √ 2y/ay




c. Draw a figure or diagram that illustrates the given problem.

1
Expert's answer
2022-05-17T08:57:28-0400


L=v02H/g,t=2H/gL=v_0\sqrt{2H/g},\quad t=\sqrt{2H/g}


(a)

v0=Lg/2H=3009.8/2600=27.1m/sv_0=L\sqrt{g/2H}\\ =300*\sqrt{9.8/2*600}=27.1\:\rm m/s

(b)

v=v02+2gH=27.12+29.8600=112m/sv=\sqrt{v_0^2+2gH}\\ =\sqrt{27.1^2+2*9.8*600}=112\:\rm m/s

(c)

t=2600/9.8=11st=\sqrt{2*600/9.8}=11\:\rm s




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