Answer to Question #341548 in Physics for alen

Question

 A positive charge, q = +35 nC, is on the y-axis at y = +5.00 cm. (a) Determine the magnitude

and direction of the electric field at the origin. (b) What will be the magnitude and direction

of the electric field at the origin if the charge is -20 nC?

Answer 1

(a)

$$E=k\frac{q}{r^2}$$

$$E=9*10^9*\frac{35*10^{-9}}{0.05^2}=1.26*10^{5}\:\rm N/C$$

Field is directed toward negative x-axis.

(b)

$$E=9*10^9*\frac{20*10^{-9}}{0.05^2}=7.2*10^{4}\:\rm N/C$$

Field is directed toward positive x-axis.