Question

A uniform magnetic field its intensity is 3x10-3 T passes an area of the coil with 100 turns which makes 60 angles with the coil. What is the area of the coil if the magnetic flux is 0.15 Wb?

Answer 1

$$\Phi=NBA\cos\theta$$

$$A=\frac{\Phi}{NB\cos\theta}$$

$$A=\frac{0.15}{100*3*10^{-3}\cos30^\circ}=0.577\:\rm m^2$$