Answer to Question #339879 in Physics for Uwbxjsja

Question

In a magnetic field of 14x10^-4 T a 4.2x10^-6 C flows at a velocity of 4x10^6 m/s. The angle is

90 degrees. How strong is the magnetic force operating on the charge?

Answer 1

$$F=qvB\sin\theta\\ =4.2*10^{-6}*4*10^6*14*10^{-4}*\sin90^\circ\\ =0.024\:\rm N$$