Question

A bullet fired at an angle θ = 60degress with a velocity of 30 m/s.

Acceleration due to gravity is 10 m/s2. What is the time interval to

reach the maximum height?

Answer 1

$$\Delta t=\frac{v_0\sin\theta}{g}=\frac{30\sin60^\circ}{10}=2.6\;\rm s$$