Answer to Question #339195 in Physics for Favour

Question #339195

Two equal charges are placed 100m a part of the force of attraction between them is 0.2N,calculate the value of the two equal charges

Expert's answer

"F=k\\frac{q_1q_2}{r^2}=k\\frac{q^2}{r^2}"

"q=\\sqrt{\\frac{Fr^2}{k}}=\\sqrt{\\frac{0.2*100^2}{9*10^9}}=4.7*10^{-4}\\:\\rm C"

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