Answer to Question #336417 in Physics for Jahah

Question

A 0.5kg egg is falling at a speed of 10 m/s before hitting the ground. What is the force of impact if the impact time is measured to be 3.0 milliseconds?

Answer 1

The Newton's second law says

$$F=ma=m\frac{\Delta v}{\Delta t}$$

$$F=\rm 0.5\: kg*\frac{10\: m/s}{3.0*10^{-3}\: s}=1.7*10^3\: N$$