Question #335909

A 10-g rifle bullets requires a speed of a 400 m/s in traversing a barrel 50 cm long. find the average acceleration and acceleration force?

1
Expert's answer
2022-05-02T13:42:20-0400

Given:

m=0.01kgm=0.01\:\rm kg

v0=400m/sv_0=400\:\rm m/s

vf=0m/sv_f=0\:\rm m/s

d=0.5md=0.5\:\rm m


The energy-work theorem says

ΔEk=W\Delta E_k=W

mv022=Fd\frac{mv_0^2}{2}=Fd

The average force

F=mv022d=0.01400220.5=1600NF=\frac{mv_0^2}{2d}=\frac{0.01*400^2}{2*0.5}=1600\:\rm N

Acceleration

a=Fm=16000.01=1.6105m/s2a=\frac{F}{m}=\frac{1600}{0.01}=1.6*10^5\:\rm m/s^2


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