Question

a volleyball is spiked so that its incoming velocity of +4.89m/s is changed to an outgoing velocity of -11.7m/s. The mass of the volleyball is 377g. What is the magnitude of the impulse that the player applies to the ball?

Answer 1

The magnitude of the impulse that the player applies to the ball

$$\Delta p=m\Delta v\\ ={0.377\:\rm kg*(4.89\: m/s-(-11.7 \: m/s))}\\ =6.25\:\rm kg\cdot m/s$$