Answer to Question #335613 in Physics for Britz3

Question #335613

The force between two electrical charges is 0.4 N. What would be the force if the charges are doubled, and the distance between them increased by 100%?

Expert's answer

"F=k\\frac{q_1q_2}{r^2}"

"F'=k\\frac{2q_1*2q_2}{(2r)^2}=k\\frac{q_1q_2}{r^2}=F=0.4\\:\\rm N"

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