Question #334576

An ideal gas that occupies 1.2m3 at a pressure of 1 x 105 Pa and a temperature of 27C is compressed to a volume of 0.6m3 and heated to a temperature of 227C. What is the new pressure? 


1
Expert's answer
2022-04-28T16:42:19-0400
P1V1T1=P2V2T2\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

P2=P1V1T2V2T1P_2=P_1\frac{V_1T_2}{V_2T_1}

P2=1.0105×1.2(27+273)0.6(227+273)=1.2105PaP_2=1.0*10^5\times\frac{1.2*(27+273)}{0.6*(227+273)}=1.2*10^5\:\rm Pa


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS