Question #334272

A pool ball leaves a 0.60-meter high table with an initial velocity of 2.4 m/s. Predict the time required for the pool ball to fall to the ground and the horizontal distance between the table's edge and the ball's landing location.


1
Expert's answer
2022-04-27T13:33:54-0400

The time required for the pool ball to fall to the ground

t=2H/g=20.60/9.8=0.35st=\sqrt{2H/g}\\ =\sqrt{2*0.60/9.8}=0.35\:\rm s

The horizontal distance between the table's edge and the ball's landing location

L=v0t=2.40.35=0.84mL=v_0t=2.4*0.35=0.84\:\rm m


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