Answer to Question #334147 in Physics for Stephanie

Question #334147

a capacitor that has air between its plates is connected across a potential differences of 12.0 v and stores 48.0 mu c. what is the capacitance of capacitor?

Expert's answer

The capacitance

C=\frac{q}{V}=\rm\frac{48.0*10^{-6}\:C}{12.0\: V}=4.00*10^{-6}\: F=4.00\: \mu F

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