Question #333339

Find the magnitude and direction of the vector represented by each of the following pairs of components:


(a) 𝐴𝑥 = 3.0 𝑐𝑚, 𝐴𝑦 = −4.0 𝑐𝑚;


(b) 𝐴𝑥 = −5.0 𝑚, 𝐴𝑦 = −12.0 𝑚;


(c) 𝐴𝑥 = −2.0 𝑘𝑚, 𝐴𝑦 = 3.0 𝑘𝑚.



1
Expert's answer
2022-04-27T13:34:42-0400
A=Ax2+Ay2A=\sqrt{A_x^2+A_y^2}

θ=tan1AyAx\theta=\tan^{-1}\frac{A_y}{A_x}

(a)

A=(3.0)2+(4.0)2=5.0cmA=\sqrt{(3.0)^2+(-4.0)^2}=5.0\:\rm cm

θ=tan14.03.0=307\theta=\tan^{-1}\frac{-4.0}{3.0}=307^\circ

(b)

A=(5.0)2+(12.0)2=13mA=\sqrt{(-5.0)^2+(-12.0)^2}=13\:\rm m

θ=tan112.05.0=247\theta=\tan^{-1}\frac{-12.0}{-5.0}=247^\circ

(c)

A=(2.0)2+(3.0)2=3.6kmA=\sqrt{(-2.0)^2+(3.0)^2}=3.6\:\rm km

θ=tan13.02.0=124\theta=\tan^{-1}\frac{3.0}{-2.0}=124^\circ


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