Question

calculate the capacitance of a capacitor if it stores a charge of 2.3x10-4 when delivered with a voltage of 4x103V

Answer 1

Given:

$q=2.3*10^{-4}\:\rm C$

$V=4*10^{3}\:\rm V$

The capacitance

$$C=\frac{q}{V}=\frac{2.3*10^{-4}}{4*10^3}=5.75*10^{-8}\:\rm F$$