Answer to Question #331234 in Physics for Sam

Question #331234

You pull a box using a rope, which is directed 30 degrees above the horizontal. You apply a constant force of 30 N, and you move the box 5 m along the ground. What work did you do in Joules?

1
Expert's answer
2022-04-21T17:44:57-0400

By definition, the work is the scalar product of the force and displacement:


W=FdW = \mathbf{F}\cdot \mathbf{d}

Since the box is displaced along the horizontal direction, and the force makes θ=30°\theta=30\degree with horizontal, the formula for the scalar product becomes:


W=FdcosθW = Fd\cos\theta

where F=30N,d=5mF = 30N, d = 5m. Thus, obtain:


W=30N5mcos30°130JW = 30N\cdot 5m\cdot \cos30\degree \approx 130J

Answer. 130 J.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment