Question #330918

Charges are equal and opposite on two parallel plates. When space was evacuated, the electric field was 2.80 x 105 V/m. When it was filled with a dielectric material, the electric field was 1.20x105 V/m. What is the dielectric constant? What is the material?

1
Expert's answer
2022-04-19T12:06:04-0400
κ=EE0=2.801051.20105=2.33\kappa=\frac{E}{E_0}=\frac{2.80*10^5}{1.20*10^5}=2.33


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