Question #330045

A ball is thrown




horizontally with an initial velocity of




30m/s from a height of 2 m. How long will it take to reach the ground? How far will it go?

Expert's answer

The time of motion

t=2Hg=229.8=0.64st=\sqrt{\frac{2H}{g}}=\sqrt{\frac{2*2}{9.8}}=0.64\:\rm s

The horizontal distance

d=v0t=300.64=19md=v_0t=30*0.64=19\:\rm m


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