Question #329825

A car is stopped at a traffic light. It then travels along a straight road so that its distance


from the light is given by x(t) = bt


2 − ct


3


, where b = 2.40m/s


2


and c = 0.120 m/s


3


.



(a) Calculate the average velocity of the car for the time interval t = 0 to t = 10 seconds.


(b) Calculate the instantaneous velocity of the car at t = 0,t = 5s, and t = 10s.


(c ) How long after starting from rest is the car again at rest?

1
Expert's answer
2022-04-17T17:05:55-0400
x(t)=bt2ct3=2.40t20.120t3x(t)=bt^2-ct^3\\ =2.40t^2-0.120t^3

(a)

vave=ΔvΔt=2.401020.12010310=12m/sv_{ave}=\frac{\Delta v}{\Delta t}=\frac{2.40*10^2-0.120*10^3}{10}=12\:\rm m/s

(b)

v(t)=x(t)=4.80t0.360t2v(t)=x'(t)=4.80t-0.360t^2

v(0)=4.8000.36002=0m/sv(0)=4.80*0-0.360*0^2=0\:\rm m/s

v(5)=4.8050.36052=15m/sv(5)=4.80*5-0.360*5^2=15\:\rm m/s

v(10)=4.80100.360102=12m/sv(10)=4.80*10-0.360*10^2=12\:\rm m/s

(c)

v=4.80t0.360t2=0v=4.80*t-0.360*t^2=0

t=4.800.360=13.3st=\frac{4.80}{0.360}=13.3\:\rm s


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