Question #329401

A pendulum is formed from a small rock with mass of 0.10 kg that is fastened to a massless string




with length 0.750 m. It is swinging so as to make a maximum angle of 45.0 with the vertical. Air




resistance is negligible. What is the tension in the string as it passes through the vertical?

Expert's answer

The tension in the string as pendulum passes through the vertical

T=mg+mv2lT=mg+\frac{mv^2}{l}

The speed of rock at this instant

v=2gl(1cosθ)v=\sqrt{2gl(1-cos\theta)}

Hence

T=mg+2mg(1cosθ)=mg(3cosθ)=0.109.8(3cos45)=2.25NT=mg+2mg(1-cos\theta)=mg(3-\cos\theta)\\ =0.10*9.8*(3-\cos 45^\circ)=2.25\:\rm N


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