Answer to Question #327067 in Physics for Beverly

Question

A 60kg survivor of a shipwreck sits on a block of wood having volume of 1.6m³. Two birds of the block of the wood is under seawater (density = 1025 kg/m³ .find a the volume of diaplaced seawater by the block of wood, b. buoyant force on the block of wood and the survivor

Answer 1

(a) the volume of displaced seawater by the block of wood

$V_d=\frac{m}{\rho_w}=\frac{60\:\rm kg/m^3}{1025\:\rm kg/m^3}=5.85*10^{-2}\:\rm m^3$

(b) the buoyant force on the block

$F_b=mg\\ =\rm 60\: kg*9.8\: N/kg=588\: N$