Answer to Question #326607 in Physics for Cass

Question

If a 1.35 tonne car accelerate from 15.0km/h to 75km/h on a flat road in 4.00 seconds,

A. What is the distance travelled?

Answer 1

A. The distance travelled by a car

$$d=\frac{v_i+v_f}{2}t$$

$$d=\frac{(15.0+75.0)\div3.6\:\rm m/s}{2}*4.00\:\rm s=50\:\rm m$$