Question #326536

A 70kg box is slid along a horizontal floor by a horizontal 400Nt force. Find the distance travelled by the box in 5 seconds if

a) there is no friction

b) coefficient of friction = 0.20


1
Expert's answer
2022-04-11T12:03:16-0400

(a)

a=Fnetm=40070=5.7m/s2a=\frac{F_{net}}{m}=\frac{400}{70}=5.7\:\rm m/s^2

d=at2/2=5.752/2=71  md=at^2/2=5.7*5^2/2=71\;\rm m

(b)

a=Fnetm=400709.80.270=3.75m/s2a=\frac{F_{net}}{m}=\frac{400-70*9.8*0.2}{70}=3.75\:\rm m/s^2

d=at2/2=3.7552/2=47  md=at^2/2=3.75*5^2/2=47\;\rm m


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