Question #326062

An elevator is moving up at a constant velocity of 2.50 m/s the man has a mass of 85.0 kg how large is the force exerts on the man


Expert's answer

F=m(g+a)=85.0(9.81+0)=834NF=m(g+a)\\ =85.0*(9.81+0)=834\:\rm N


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