Answer to Question #325323 in Physics for dan

Question #325323

A force of 250 N exerted at an angle of 30° above the horizontal is needed to keep a 90 kg block moving along a

cement floor. Find the coefficient of kinetic friction.

Expert's answer

"\\mu=\\frac{F\\cos\\theta}{mg-F\\sin\\theta}"

"\\mu=\\frac{250*\\cos30^\\circ}{90*9.8-250*\\sin30^\\circ}=0.286"

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