Question

A golf ball with a mass of 0.06 kg is subjected to an impulse that causes it to move with a velocity of 50 m/s. If the golf club and the ball are in contact for 5x10^-3 second, what average net force acts on the ball? 

Answer 1

The Newton's second law says

$$F=\frac{m\Delta v}{\Delta t}$$ $$F=\frac{0.06*50}{5*10^{-3}}=600\:\rm N$$