Question

A 55.0 m wire carries a current of 2.25 A in a location where Earth’s

magnetic field is 4.5 x 10^-3 T. The wire experiences a force of 0.15 N. Find

the angle between the wire and the magnetic field.

Answer 1

The magnetic field force on a wire with current

$$F=BIl\sin\theta$$

Hence

$$\theta=\sin^{-1}\frac{F}{BIl}$$

$$\theta=\sin^{-1}\frac{0.15}{4.5*10^{-3}*2.25*55.0}=15.6^\circ$$