Question #324229

A circuit has a resistor with a resistance of 3Ω followed by three parallel branches, each holding a resistor with a resistance of 5Ω. What is the total equivalent resitance of the


circuit?

Expert's answer

The total equivalent resistance

R=R1+R23=3Ω+5Ω3=4.7ΩR=R_1+\frac{R_2}{3}\\ =3\:\Omega+\frac{5\:\Omega}{3}=4.7\:\Omega


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