Answer to Question #324168 in Physics for Akiii

Question

A charge of 6x10^-7C is transferred from infinity to point A. If the work done to do this is 1.2x10^-5J what is the potential point A

Answer 1

The potential at point A:

$$V=\frac{W}{q}=\rm\frac{1.2*10^{-5}\: J}{6*10^{-7}\: C}=20\: V$$