Answer to Question #323798 in Physics for pogi

Question #323798

A disk with a diameter of 30 cm speeds up from 20 rad/s to 40 rad/s in 20s. (a) How many revolutions will the disk go through during that time period? (b.) What is the average linear acceleration of the disk?


1
Expert's answer
2022-04-05T19:19:25-0400

(a)

N=θ2π=12πωf+ωi2tN=\frac{\theta}{2\pi}=\frac{1}{2\pi}\frac{\omega_f+\omega_i}{2}t

N=12π40+20220=96revN=\frac{1}{2\pi}\frac{40+20}{2}*20=96\:\rm rev

(b)

α=ωfωit=402020=1rad/s2\alpha=\frac{\omega_f-\omega_i}{t}=\frac{40-20}{20}=1\:\rm rad/s^2

a=αR=1rad/s20.15m=0.15m/s2a=\alpha R=1\:\rm rad/s^2*0.15\: m=0.15\: m/s^2


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