Question

Find the KE of a 500-g object after 1.0 meter of its fall from the top of a building. And construct the free-body diagram?

Answer 1

Given:

$m=0.5\:\rm kg$

$h=1.0\:\rm m$

$g=9.8\:\rm N/kg$

The law of conservation of energy says

$$\frac{mv^2}{2}=mgh=0.5*1.0*9.8=4.9\:\rm J$$

The free-body diagram is as follows