Question #320381

A 1.5 N stone is thrown vertically upward with an initial speed of 15 m/s. Calculate



a. P.E at the maximum height


b. K.E at the instant it will strike the ground


c. P.E after 1 s


d. K.E after 1 s



1
Expert's answer
2022-03-31T11:48:46-0400

(a)

PEmax=mghmax=mv022=1.5/9.81522=17JPE_{max}=mgh_{max}=\frac{mv_0^2}{2}\\ =\frac{1.5/9.8*15^2}{2}=17\:\rm J

(b)

KEf=KEi=mv022=1.5/9.81522=17JKE_f=KE_i=\frac{mv_0^2}{2}\\ =\frac{1.5/9.8*15^2}{2}=17\:\rm J

(c)

PE=mgh=mg(v0tgt2/2)=1.5(1519.812/2)=15JPE=mgh=mg(v_0t-gt^2/2)\\ =1.5(15*1-9.8*1^2/2)=15\:\rm J

(d)

KE=KEiPE=17J15J=2JKE=KE_i-PE\\ =17\:\rm J-15\: J=2\: J


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Comments

AAB
01.04.22, 04:00

Thank you!

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