Question #319728

A sinusoidal wave travelling in the positive x-direction has a wavelength of 0.4 m, an amplitude of 20 cm, and a period of 4 seconds. The transverse position of an element of the medium at x = 0 and t = 0 is y = 10 cm, and the element is moving downward. The expression of the wave function describing this wave is:


1
Expert's answer
2022-03-28T14:24:13-0400

In general, the sinusoidal wave is described by

y(x,t)=Asin(ωtkx+ϕ0)y(x,t)=A\sin(\omega t-kx+\phi_0)

In our case,

A=0.2mω=2π/T=2π/4=0.5πk=2π/λ=2π/0.4=5πϕ0=π/2A=0.2{\:\rm m}\\ \omega=2\pi/T=2\pi/4=0.5\pi\\ k=2\pi/\lambda=2\pi/0.4=5\pi\\ \phi_0=\pi/2

Finally

y(x,t)=0.2sin(0.5πt5πx+π/2)=0.2cos(0.5πt5πx)y(x,t)=0.2\sin(0.5\pi t-5\pi x+\pi/2)\\ =0.2\cos(0.5\pi t-5\pi x)


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