A 55.0m wire carries a current of 2.25 A in a location where Earth's magnetic field is 4.5 x10-3 T. Ther wire experiences a force of 0.15 N. Find the angle between the wire and the magnetic field.
The Lorentz force
"F=BIl\\sin\\theta"Hence, the angle between the wire and the magnetic field
"\\theta=\\tan^{-1}\\frac{F}{BIl}""\\theta=\\tan^{-1}\\frac{0.15}{4.5*10^{-3}*2.25*0.55}=88^\\circ"
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