Answer to Question #319344 in Physics for Yusuf

Question #319344

A spring is stretched 40mm by a force of 15N. What is the work done by the force


1
Expert's answer
2022-03-28T11:02:47-0400

The work done by the force

W=kx22=Fx2=15N0.04  m2=0.3JW=\frac{kx^2}{2}=\frac{Fx}{2}\\ =\frac{15\:\rm N*0.04\;\rm m}{2}=0.3\:\rm J


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