Answer to Question #318280 in Physics for Jiren

Question #318280

1-5 The ball is tied to a string to whirl it having a radius of 40.0 cm at a velocity of 2.5 m/s. What will be

the acceleration of the ball?

Expert's answer

The centripetal acceleration

"a=\\frac{v^2}{R}=\\frac{2.5^2}{0.20}=31\\:\\rm m\/s^2"

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