Question #316860

what is the electric flux passing through a Gaussian surface that contains 2 protons and 1 electron?


1
Expert's answer
2022-03-24T11:00:33-0400

The Gauss's law says

ϕ=EdA=qencϵ0\phi=\oint EdA=\frac{q_{enc}}{\epsilon_0}

ϕ=2eeϵ0=eϵ0\phi=\frac{2e-e}{\epsilon_0}=\frac{e}{\epsilon_0}

ϕ=1.610198.851012=1.8108Nm2/C\phi=\frac{1.6*10^{-19}}{8.85*10^{-12}}=1.8*10^{-8}\:\rm N\cdot m^2/C


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