Question #316466

A sinusoidal wave traveling in the positive x direction has an amplitude of 15.0 cm, a wavelength of 40.0 cm, and a frequency of 8.00 Hz. The vertical position of an element of the medium at t = 0 and x = 0 is also 15.0 cm, Determine the phase constant , and write a general expression for the wave function 


1
Expert's answer
2022-03-23T07:15:16-0400

Given:

A=15.0cmA=15.0\:\rm cm

λ=40.0cm\lambda=40.0\:\rm cm

f=8.00Hzf=8.00\:\rm Hz

y(0,0)=15.0cmy(0,0)=15.0\:\rm cm


The general expression for the wave function

y(x,t)=Acos(2πλx2πft+ϕ0)y(x,t)=A\cos\left(\frac{2\pi}{\lambda}x-2\pi ft+\phi_0\right)


y(x,t)=15.0cos(2π40.0x2π8.00t+ϕ0)y(x,t)=15.0\cos\left(\frac{2\pi}{40.0}x-2\pi*8.00t+\phi_0\right)

y(x,t)=15.0cos(0.157x20.2t+ϕ0)y(x,t)=15.0\cos\left(0.157x-20.2t+\phi_0\right)

The initial condition gives

y(0,0)=15.0cos(ϕ0)=15.0y(0,0)=15.0\cos\left(\phi_0\right)=15.0

Hence

cos(ϕ0)=1,ϕ0=0\cos\left(\phi_0\right)=1,\quad \phi_0=0

Finally

y(x,t)=15.0cos(0.157x20.2t)y(x,t)=15.0\cos\left(0.157x-20.2t\right)


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