Answer to Question #316298 in Physics for yaw

Question

A stone is thrown into a well 6m deep. The stone is thrown from rest. How

long will it take before you hear the stone hit the floor of the well. Assume

speed of sound is 2m/s (this is not the actual speed of sound, please!!)?

Answer 1

The total time that elapsed as you thrown a stone and you hear the stone hit the floor of the well

$$t=t_1+t_2=\sqrt{2h/g}+h/v_s\\ =\sqrt{2*6/9.8}+6/2=4.1\;\rm s$$