A 125 m long transmission wire is stretched between two vertical posts. It carries a current of 35.0 A and experiences a force of 0.25 N due to Earth's magnetic field. What is the value of Earth's magnetic field at the location of the wire if the wire is 60° with it?
The magnetic field force is given by
"F=BIl\\sin\\theta"Hence, the strength of magnetic field
"B=\\frac{F}{Il\\sin\\theta}\\\\\n=\\frac{0.25}{35.0*125*\\sin60^\\circ}=6.6*10^{-5}\\:\\rm T"
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