Question

A parallel plate air capacitor has a capacitance of 5 F. What is the electric field between two parallel metal plates separated by 2,5 cm with a potential difference of 3000V?

Answer 1

The electric field between plates of capacitor

$$E=\frac{V}{d}\\ =\rm\frac{3000\: V}{0.025\: m}=1.2\times 10^5\: V/m$$