Answer to Question #313812 in Physics for Carl

Question

A stone is thrown straight upward with a velocity of 30 m/s. What was its maximum height?, b) What is the time taken to reach the maximum height?, c) What is the velocity of the stone when it is 60 m from the ground? (Assume the ground as the initial frame of reference)

Answer 1

(a)

$h_{\max}=\frac{v_0^2}{2g}=\frac{30^2}{2\times 9.8}=46\:\rm m$

(b)

$t=\frac{v_0}{g}=\frac{30}{9.8}=3.1\:\rm s$

(c) impossible