Question

Find the Potential Energy of a charge with 99 μC with a potential difference of 15 V

Answer 1

The Potential Energy of a charge 

$$E_p=\frac{qV}{2}=\rm\frac{(99\times 10^{-6}\: C)\times(15\: V)}{2}=7.4\times 10^{-4}\: J$$