Find the electric flux through a cylinder with a distance of 24 cm and a height of 37 cm with a charge of 5.42 μC. ( use the general formula of flux and the area of cylinder is 2𝜋rh + 2𝜋r²)
The electric flux is given by
"\\Phi=\\oint EdA=\\frac{q}{\\epsilon_0}""\\Phi=\\frac{5.42\\times 10^{-6}}{8.85\\times 10^{-12}}=6.12\\times 10^5\\:\\rm N\\cdot m^2\/C"
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