Answer to Question #313702 in Physics for jane

Question

A stone is thrown straight upward with a velocity of 30 m/s. What was its maximum height?, b) What is the time taken to reach the maximum height?, c) What is the velocity of the stone when it is 60 m from the ground? (Assume the ground as the initial frame of reference)

Answer 1

(a)

$$h_{\max}=\frac{v_0^2}{2g}=\frac{30^2}{2\times 9.8}=46\:\rm m$$

(b)

$$t=\frac{v_0}{g}=\frac{30}{9.8}=3.1\:\rm s$$

(c) The maximum height of a stone above the ground is 46 m, so it will never be being at level 60 m above the ground.