Answer to Question #313698 in Physics for jane

Question

An object starts from rest with a constant acceleration of 10 ft/s² along a straight road. Determine the velocity after 3.5 sec, b) the average velocity for the 3.5 seconds interval, and c) the distance travelled in this given time.

Answer 1

(a)

$v=v_0+at\\ =\rm 0\: ft/s+10\: ft/s^2\times 3.5\: s=35\: ft/s$

(b)

$v_{\rm ave}=\frac{v_0+v}{2}\\ =\rm\frac{0\: ft/s+35\: ft/s}{2}=17.5\: ft/s$

(c)

$d=v_{\rm ave}t\\ =\rm 17.5\: ft/s\times 3.5\: s=61.25\: ft$