Question #313455

A body vibrate in simple harmonic motion with a frequency of 50hz and an amplitude of 4cm. Find



1.period



2. Acceleration at the middle and at the end of the path of oscillation

Expert's answer

1.

The period of oscillations

T=1f=150Hz=0.02sT=\frac{1}{f}=\frac{1}{50\rm\: Hz}=0.02\:\rm s

2.

The acceleration at the middle point is zero.

The acceleration at the end point is equal

amax=Aω2=4π2Af2=4×3.142×0.04  m×(50Hz)2=3944m/s2a_{\max}=A\omega^2=4\pi^2Af^2\\ =4\times 3.14^2\times0.04\;\rm m\times (50\: Hz)^2=3944\: m/s^2


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