Answer to Question #313069 in Physics for dsasa

Question #313069

Phineas is pushing a 11.13-kg box of tools with a force of 47 N directed at an angle of 83° downward from the horizontal. How fast is the cart going after the acceleration from rest if their backyard is 77 cm away from the garage?


1
Expert's answer
2022-03-17T09:30:58-0400

The horizontal component of applied force

Fx=Fcosθ=47Ncos83=5.73NF_x=F\cos\theta\\ =47\:\rm N*cos83^\circ=5.73\: N

The acceleration of the box

a=Fxm=5.73N11.13kg=0.515m/s2a=\frac{F_x}{m}=\frac{5.73\:\rm N}{11.13\:\rm kg}=0.515\:\rm m/s^2

The final velocity

v=2ad=20.515m/s20.77m=0.89m/sv=\sqrt{2ad}\\ =\sqrt{2*0.515\:\rm m/s^2*0.77\: m}=0.89\:\rm m/s


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