Question #312681

A 12 mA steady current is flowing on a copper wire at a time interval of one


minute. Calculate the number of electrons passing on the copper wire

Expert's answer

The net charge passing through the copper wire

q=It=12∗10−3∗60=0.72 Cq=It\\ =12*10^{-3}*60=0.72\:\rm C

The corresponding number of electrons

N=qe=0.721.6∗10−19=4.5∗1018N=\frac{q}{e}=\frac{0.72}{1.6*10^{-19}}=4.5*10^{18}


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