A 12 mA steady current is flowing on a copper wire at a time interval of one
minute. Calculate the number of electrons passing on the copper wire
The net charge passing through the copper wire
"q=It\\\\\n=12*10^{-3}*60=0.72\\:\\rm C"The corresponding number of electrons
"N=\\frac{q}{e}=\\frac{0.72}{1.6*10^{-19}}=4.5*10^{18}"
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