Question

How much charge is on each plate of a 4.00-µF capacitor when it is connected

to a 12.0-V battery (? (b) If this same capacitor is connected to a 1.50-V

battery, what charge is stored?

Answer 1

(a) the charge on the plates of capacitor

$$q=CV=4.00*10^{-6}*12.0=4.8*10^{-5}\:\rm C$$

(b)

$$q=CV=4.00*10^{-6}*1.50=6.0*10^{-6}\:\rm C$$